- Poker Bad Beat Jackpot Odds Slot Machines
- Poker Bad Beat Jackpot Odds Lottery
- Poker Bad Beat Jackpot Odds Jackpot
To help you shake off a bad beat, we'll toss a bonus your way. Did a four of a kind or better beat your aces full of kings? Collect a Bad Beat Bonus of 100X the big blind, and you'll pocket up to $1,000. Brush the dirt off your shoulders and get back in the game.
In order to claim the bonus
As the odds of hitting a bad beat in poker increases, the jackpot will be hit more frequently, subsequently meaning the amount to be won will usually be lower. Bad Beat Poker Conclusion. Bad beats in poker are just a normal part of the game. The second thing to understand is that the odds indicate the probability of the bad beat jackpot hitting at any given time. If the probabilities hold true, the jackpot will hit for the quad 8’s requirement every 156,250 hands. HOWEVER, that does not mean that every hand past the 156,250th hand, the jackpot is then due and therefore there are higher odds for it to hit.
- Both pocket cards must be used by both the losing and winning hand.
- Three or more players must be dealt into the hand.
- Both the winning and losing hand must go to showdown.
- All hands must be played independently. If you reveal your hand or instruct others on how to act, you won't be eligible.
- You must be playing Texas Hold'em cash games. Tournaments not included.
If your bad beat satisfies these requirements, you've got 48 hours to submit your hand number and table number to poker@ignitioncasino.eu. This rollover-free bonus will be processed in up to 48 hours.
jodybingo
My club is now offering a 'super beat jackpot' on top of our usual bad beat jackpot. The super beat jackpot requires that 5 players be dealt in to a hand, both players involved in the bad beat hand use both pocket cards and the losing hand must be a queen high straight flush.
What are the odds of having a queen high straight flush vs a royal flush with a minimum of 5 players (not sure if 5 players would come into calculations here) with both players using both pocket cards? What would the calculation (formula) look like?
Jody Stacey
What are the odds of having a queen high straight flush vs a royal flush with a minimum of 5 players (not sure if 5 players would come into calculations here) with both players using both pocket cards? What would the calculation (formula) look like?
Jody Stacey
Ibeatyouraces
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jodybingo
My club is offering a $1M jackpot for this bad beat on our 1 anniversary weekend and want to know what the odds were
ThatDonGuy
Here's what I get for the original Super Beat:
There are 52 x 51 x 50 x 49 x 48 / 120 = 2,598,960 sets of community cards.
Of these, there are 45 x 44 / 2 = 990 that contain QJT of hearts but none of AK98 of hearts. Similarly, there are 990 in diamonds, 990 in spades, and 990 in clubs, or a total of 3960 sets of community hands that have QJT suited but none of AK98 of that suit.
Since each player has an equal chance of 'winning,' I will calculate the chance of 'somebody' winning and then divide by five to get the chance of 'you' winning.
Separate the hole cards into each player's 'first' and 'second' hole cards.
With 5 players, there are 47 x 46 x 45 x 44 x 43 / 120 = 1,533,939 sets of five cards.
One possible 'winning' set is A8 in the suit and three other cards that are neither K nor 9 in that suit; there are 43 x 42 x 41 / 6 = 12,341 of those. Similarly, there are 12,341 sets with A9, 12,341 with K8, and 12,341 with K9, for a total of 49,364 sets of 'first cards' that can still produce the jackpot.
At this point, there are 42 cards left in the deck; whichever of the A or K that one player has, he has to get the other, so there is 1/42 chance of that, and of the remaining 41 cards, the player with the 8 or 9 has to get the other one, so there is 1/41 chance of that.
The overall probability with five players is
990 / 2598960 x 49364 / 1533939 x 1/42 x 1/41 = about 1 in 140 million.
The probability of a particular player winning is 1/5 of that, or about 1 in 700 million.
There are 52 x 51 x 50 x 49 x 48 / 120 = 2,598,960 sets of community cards.
Of these, there are 45 x 44 / 2 = 990 that contain QJT of hearts but none of AK98 of hearts. Similarly, there are 990 in diamonds, 990 in spades, and 990 in clubs, or a total of 3960 sets of community hands that have QJT suited but none of AK98 of that suit.
Since each player has an equal chance of 'winning,' I will calculate the chance of 'somebody' winning and then divide by five to get the chance of 'you' winning.
Separate the hole cards into each player's 'first' and 'second' hole cards.
With 5 players, there are 47 x 46 x 45 x 44 x 43 / 120 = 1,533,939 sets of five cards.
One possible 'winning' set is A8 in the suit and three other cards that are neither K nor 9 in that suit; there are 43 x 42 x 41 / 6 = 12,341 of those. Similarly, there are 12,341 sets with A9, 12,341 with K8, and 12,341 with K9, for a total of 49,364 sets of 'first cards' that can still produce the jackpot.
At this point, there are 42 cards left in the deck; whichever of the A or K that one player has, he has to get the other, so there is 1/42 chance of that, and of the remaining 41 cards, the player with the 8 or 9 has to get the other one, so there is 1/41 chance of that.
The overall probability with five players is
990 / 2598960 x 49364 / 1533939 x 1/42 x 1/41 = about 1 in 140 million.
The probability of a particular player winning is 1/5 of that, or about 1 in 700 million.
Poker Bad Beat Jackpot Odds Slot Machines
jodybingo
thank you for the break down! i was hoping for this and not just a ratio
Ibeatyouraces
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jodybingo
In your formula above, can you explain why you are dividing by 120 for the community cards
jodybingo
I want to try and answer this one...5!! (because 5 cards are being used as community cards)? Am I right?
Poker Bad Beat Jackpot Odds Lottery
ThatDonGuy
Poker Bad Beat Jackpot Odds Jackpot
Correct - in this case, we are interested only in how many different 'sets' of the five community cards exist, regardless of their order. It doesn't matter what cards are in the flop, which one is the turn, and which one is the river.